we know that
If the ordered pair is a solution of the equation, then the ordered pair must satisfied the equation
we will proceed to solve each case to determine the solution of the problem
we have
[tex]y=8x[/tex] -------> equation [tex]1[/tex]
case a) [tex](0,8)[/tex]
[tex]x=0\\y=8[/tex]
For [tex]x=0[/tex]
substitute the value of x in the equation [tex]1[/tex] and then compare the values of y
[tex]y=8*0=0[/tex]
so
[tex]0\neq 8[/tex]
The ordered pair case a) is not solution
case b) [tex](-1,8)[/tex]
[tex]x=-1\\y=8[/tex]
For [tex]x=-1[/tex]
substitute the value of x in the equation [tex]1[/tex] and then compare the values of y
[tex]y=8*(-1)=-8[/tex]
so
[tex]-8\neq 8[/tex]
The ordered pair case b) is not solution
case c) [tex](1.5,10)[/tex]
[tex]x=1.5\\y=10[/tex]
For [tex]x=1.5[/tex]
substitute the value of x in the equation [tex]1[/tex] and then compare the values of y
[tex]y=8*1.5=12[/tex]
so
[tex]12\neq 10[/tex]
The ordered pair case c) is not solution
case d) [tex](2,16)[/tex]
[tex]x=2\\y=16[/tex]
For [tex]x=2[/tex]
substitute the value of x in the equation [tex]1[/tex] and then compare the values of y
[tex]y=8*2=16[/tex]
so
[tex]16=16[/tex]
The ordered pair case d) is a solution
therefore
the answer is
[tex](2,16)[/tex]
