Aluminum will react with bromine to form aluminum bromide (used as an acid catalyst in organic synthesis). Al(s) + Br2(l) → Al2Br6(s) [unbalanced] How many moles of Al are needed to form 2.43 mol of Al2Br6?

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joseaaronlara joseaaronlara · Answer 1 · 2020-02-19T15:22:08+01:00

Answer:

The answer to your question is 4.86 moles

Explanation:

Unbalanced Chemical reaction

Al(s) + Br₂ (l) ⇒ Al₂Br₆ (s)

Reactants Elements Products

1 Al 2

2 Br 6

Balanced chemical reaction

2 Al(s) + 3Br₂ (l) ⇒ Al₂Br₆ (s)

Reactants Elements Products

2 Al 2

6 Br 6

Moles of Al = ?

Moles of Al₂Br₆ = 2.43 moles

- Use proportions to answer this question

2 moles of Al -------------------- 1 mol of Al₂Br₆

x -------------------- 2.43 moles of Al₂Br₆

x = (2.43 x 2)/1

x = 4.86 moles of Al

samueladesida43 samueladesida43 · Answer 2 · 2021-11-16T10:47:39+01:00

4.86 moles of Al are needed to form 2.43 mol of Al2Br6.

According to this question, aluminum reacts with bromine to form aluminum bromide as follows:

However, this equation is not balanced. The balanced equation using coefficients is as follows:

According to this equation, 2 moles of Aluminum produces 1 mole of Al2Br6.

Hence, 2.43 moles of Al2Br6 will be produced from (2.43 × 2) = 4.86 moles of Al.

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