Respuesta :
Answer: The balanced equation is [tex]2KOH + H_{2}SO_{4} \rightarrow K_{2}SO_{4} + 2H_{2}O[/tex] and the concentration of the sulfuric acid solution is 0.184 M.
Explanation:
Given: [tex]V_{1}[/tex] = 27.5 mL, [tex]M_{1}[/tex] = 0.235 M
[tex]V_{2}[/tex] = 35.0 mL, [tex]M_{2}[/tex] = ?
Formula used to calculate the concentration of the sulfuric acid solution is as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]
Substitute the values into above formula as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}\\0.235 M \times 27.5 mL = M_{2} \times 35.0 mL\\M_{2} = \frac{0.235 M \times 27.5 mL}{35.0 mL}\\= 0.184 M[/tex]
The given chemical equation for given reaction is as follows.
[tex]KOH + H_{2}SO_{4} \rightarrow K_{2}SO_{4} + H_{2}O[/tex]
Number of atoms on reactant side are as follows.
- K = 1
- H = 2
- [tex]SO_{4}[/tex] = 1
- O = 1
Number of atoms on product side are as follows.
- K = 2
- H = 2
- [tex]SO_{4}[/tex] = 1
- O = 1
To balance this equation, multiply KOH by 2 on reactant side and multiply [tex]H_{2}O[/tex] by 2. Hence, the equation can be rewritten as follows.
[tex]2KOH + H_{2}SO_{4} \rightarrow K_{2}SO_{4} + 2H_{2}O[/tex]
Now, number of atoms on reactant side are as follows.
- K = 2
- H = 4
- [tex]SO_{4}[/tex] = 1
- O = 2
Number of atoms on product side are as follows.
- K = 2
- H = 4
- [tex]SO_{4}[/tex] = 1
- O = 2
Since, there are same number of atoms of both reactant and products. Therefore, the equation is now balanced.
Thus, we can conclude that the balanced equation is [tex]2KOH + H_{2}SO_{4} \rightarrow K_{2}SO_{4} + 2H_{2}O[/tex] and the concentration of the sulfuric acid solution is 0.184 M.
