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Water has a pressure of 3.00 x 105 Pa and a speed of 1.00 m/s as it flows through a horizontal pipe. At a certain point, the pipe narrows to one-fourth its original diameter. (Remember the radius is half of the diameter, so its radius will also be one-fourth its original size.) What is the speed of the water flow in the narrow section of the pipe?. a.. 16.0 m/s. c.. 16.2 m/s. b.. 12.6 m/s. d.. 22.6 m/s

Respuesta :

meerkat18
Flowrate of water is equal to the speed of flow multiplied by the area of flow:
 F = v*A = v * pi * r2. In this case, with flowrate remaining constant under given pressure, the formula is simplified to v1 * r1^2 = v2* r2^2 
1 m/s * (r1^2) = v2 * ( r1/4)2
v2 is expected to increase. The value is equal to 16 m/s

Answer:

A.) 16.0 m/s

Explanation:

ed2021

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