Answer:
[tex]3.973\times 10^{-14} kJ[/tex] is the result in kiloJoules.
Explanation:
Value of given Planck constant = h= [tex]6.626\times 10^{-34} J s/ atom[/tex]
Energy emitted by 1 atom in a 1 sec :[tex]=6.626\times 10^{-34} J[/tex]
2.00 min = [tex]2.00\times 60 seconds = 120.00 seconds[/tex]
Energy emitted by 1 atom in 120 seconds = E'
[tex]E'=6.626\times 10^{-34}J \times 120 [/tex]
Let the energy emitted by [tex]5.0\times 10^{20} atoms [/tex] in 2.00 minutes be E.
[tex]E=E'\times \text{Number of atoms}[/tex]
[tex]E=6.626\times 10^{-34} J\times 120 \times 5.0\times 10^{20}[/tex]
[tex]E=3.973\times 10^{-11} J=3.973\times 10^{-14} kJ[/tex]
(1 J = 0.001 kJ)
[tex]3.973\times 10^{-14} kJ[/tex] is the result in kiloJoules.
