Respuesta :
Answer: It must be between two ordered pair i.e. (-4,0) and (-3,0).
Step-by-step explanation:
Since we have given that
Quadratic equation : [tex]x^2+x-9[/tex]
First we use the quadratic formula to get the value of x:
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\dfrac{-1\pm\sqrt{1+36}}{2\times 1}\\\\x=\dfrac{-1\pm\sqrt{37}}{2}\\\\x=\dfrac{-1+\sqrt{37}}{2}\ or\ \dfrac{-1-\sqrt{37}}{2}\\\\x=2.54\ or\ -3.5[/tex]
Since the negative root of x is -3.5.
So, it must be between two ordered pair as follows :
(-4,0) and (-3,0).
