Respuesta :

The standard temperature and the pressure for a gas are 273 K and 1 atm (1.0 x 10⁵ Pa) respectively.

For this question, combined gas law can be added.

PV/T = K (constant)

for both situations that law can be added as;
P₁V₁/T₁ = P₂V₂/T₂

P₁ = 97 kPa                           P₂= 1.0 x 10⁵ Pa
T₁ = 303 K                             T₂ = 273 K
V₁ 140 mL                              V₂ = ?

V₂ = 122.3 mL

Hence, the volume of gas at STP = 122.3 mL