Respuesta :

To find the coordinates of the endpoints of segment M'N' you'll have to use the rule through which it was dilated.

M(-4,6) after the rule it will be (-4*1.5, 6*1.5) = M'(-6,9)
N(2,6) after the rule it will be (2*1.5, 6*15) = N'(3,9)

The answer is B. M'(-6,9) and N'(3,9)

Hope this helps :)

After the dilation according to the given rule [tex](x,y) \to (1.5x.1.5y)[/tex] the coordinates M'(-6,9) and N'(3,9) and will be determined by using given data.

Given :

  • Triangle MNP dilated according to the rule [tex](x,y) \to (1.5x.1.5y)[/tex].
  • Points - M(-4,6), N(2,6), and P(-1,1)

After the dilation according to the given rule [tex](x,y) \to (1.5x.1.5y)[/tex], the coordinates M'N'P' are given by:

[tex]\rm M(-4,6) \to M'(1.5\times -4, 1.5\times 6)[/tex]

[tex]\rm M(-4,6) \to M'(-6,9)[/tex]

[tex]\rm N(2,6) \to N'(1.5\times 2, 1.5\times 6)[/tex]

[tex]\rm N(2,6) \to N'(3,9)[/tex]

[tex]\rm P(-1,1) \to P'(1.5\times -1, 1.5\times 1)[/tex]

[tex]\rm P(-1,1) \to P'(-1.5,1.5)[/tex]

After the dilation according to the given rule [tex](x,y) \to (1.5x.1.5y)[/tex] the coordinates M'(-6,9) and N'(3,9).

For more information, refer to the link given below:

https://brainly.com/question/4700926