Volume of a cone:
[tex] V = \dfrac{1}{3} \pi r^2 h [/tex]
where
V = volume
r = radius of the base
h = height of the cone
In this case, r = 8 in., and h = 16 in.
[tex] V = \dfrac{1}{3} \pi r^2 h [/tex]
[tex] V = \dfrac{1}{3} \times 3.14 \times (8~in.)^2 \times 16~in. [/tex]
[tex] V = 1071.8~in.^3 [/tex]