we are given
to divide [tex] y^3-4y^2+7y-6 [/tex]
by (y-2)
We can use long division method
we get
[tex] Quotient=y^2-2y+3 [/tex]
[tex] Remainder=0 [/tex]
we can also write our expression as
[tex] \frac{y^3-4y^2+7y-6}{y-2} =(y^2-2y+3)+\frac{0}{(y-2)} [/tex]............Answer
