Respuesta :
let
x-------> the length of the other leg
y------> the length of the hypotenuse
we know that
y=2x----> equation 1
applying the Pythagoras theorem
y²=96²+x²--------> equation 2
substitute equation 1 in equation 2
[2x]²=96²+x²-----> 4x²-x²-96²=0-----> 3x²-9216=0
the answer is
3x2 - 9216 = 0
x-------> the length of the other leg
y------> the length of the hypotenuse
we know that
y=2x----> equation 1
applying the Pythagoras theorem
y²=96²+x²--------> equation 2
substitute equation 1 in equation 2
[2x]²=96²+x²-----> 4x²-x²-96²=0-----> 3x²-9216=0
the answer is
3x2 - 9216 = 0