kendraaf8
contestada

a softball diamond is a square 60 ft on a side. what is the length from home to second base? (using pythagorean theorem)

Respuesta :

CharlesTheDillPickle
60^2 + 60^2 = SH(or c^2) (second to home) 

60^2 = 3600 +3600 = 7200 

take sqrt of 7200 you get 84.85 

therefor the distance from second to home is 84.85 ft

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