Respuesta :

penyou
Using JAVA:
int sum = 0;       
int k = 1;       
while(sum  <= 2000) {           
sum += 3*k*k;           
 k++;       
 }               
System.out.println(k);

Output: 14

Which means it will take 14 terms for the series to surpass 2000


geerky42
I am assuming k starts at 0. Python code (or pseudocode) would be this:
-------------------------------
S = 0
count_term = 0
k = 0
while S <= 2000:     S = S + 3*k**2
    count_term = count_term + 1     k = k + 1

print(count_term)
-------------------------------

It will print 14

If k should start at other number then just replace number at third line and execute it.

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