Answer:
B. 18
Step-by-step explanation:
For the function
[tex]f(x)=\left\{\begin{array}{l}x+9,\ \ x<9\\27-x,\ \ x\ge 9\end{array}\right.[/tex]
we can find the value of the function for all x that are very close to 9 but are less than 9 and for all values of x that are very close to 9 but are greater than 9.
1. For [tex]x<9:[/tex]
[tex]\lim \limits_{x\rightarrow 9}f(x)=\lim \limits_{x\rightarrow 9}(x+9)=9+9=18[/tex]
2. For [tex]x\ge 9:[/tex]
[tex]\lim \limits_{x\rightarrow 9}f(x)=\lim \limits_{x\rightarrow 9}(27-x)=27-9=18[/tex]
So, limit exists and is equal to 18.
