Question 9(Multiple Choice Worth 6 points)

(05.01 LC)

The figure below shows triangle NRM with r2 = m2 + n2:

Triangle NRM has legs m and n, and r is the length of its longest side.

Ben constructed a right triangle EFD with legs m and n, as shown below:

Triangle EFD has legs m and n and hypotenuse f.

He made the following table to prove that triangle NRM is a right triangle:


Statement Reason
1. r2 = m2 + n2 Given
2. f2 = m2 + n2 Pythagorean Theorem
3. f2 = r2 Substitution
4. f = r Square Root Property of Equality
5. Triangle NRM is congruent to triangle EFD SSS Postulate
6. Angle NRM is a right angle ?
7. Triangle NRM is a right triangle Angle NRM is a right angle

Which reason best fits statement 6?
Triangle Proportionality Theorem
All sides of both the triangles are equal
Corresponding parts of congruent triangles are congruent
Triangle EFD has two angles which measure less than 90°

Question 9Multiple Choice Worth 6 points 0501 LC The figure below shows triangle NRM with r2 m2 n2 Triangle NRM has legs m and n and r is the length of its long class=
Question 9Multiple Choice Worth 6 points 0501 LC The figure below shows triangle NRM with r2 m2 n2 Triangle NRM has legs m and n and r is the length of its long class=
Question 9Multiple Choice Worth 6 points 0501 LC The figure below shows triangle NRM with r2 m2 n2 Triangle NRM has legs m and n and r is the length of its long class=

Respuesta :

Answer: Corresponding parts of congruent triangles are congruent.


Step-by-step explanation:

When two triangles are congruent then their corresponding parts of are also congruent.

In the given proof, Statement 5 says Δ NRM≅ Δ EFD

which provides that ∠NRM=∠EFD=90 ° because of the property that corresponding parts of congruent triangles are congruent.

Therefore, Corresponding parts of congruent triangles are congruent.

best fits statement 6.



Answer:

SSS postulate

Step-by-step explanation:

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