Respuesta :
The function would be
[tex]f(h)=4(2)^h[/tex].
This is in the general form
[tex]f(x)=a(b)^x[/tex], where a is the initial value, b is the rate it increases by, and x is the amount of time. For our function, the initial value is 4 and the rate it increases by is 2.
[tex]f(h)=4(2)^h[/tex].
This is in the general form
[tex]f(x)=a(b)^x[/tex], where a is the initial value, b is the rate it increases by, and x is the amount of time. For our function, the initial value is 4 and the rate it increases by is 2.
The function to represent the number of cells present at the end of h hours if there are initially 4 of these cells is [tex]\rm n = 4(2)^h[/tex]
Given that
A particular type of cell doubles in number every hour.
We have to determine
Which function can be used to find the number of cells present at the end of h hours if there are initially 4 of these cells.
According to the question
The number of cells denoted with n.
A particular type of cell doubles in number every hour.
Therefore, the number of bacteria after every hour will form a geometric series.
What is Geometric Progression?
If each term is a multiple of the next term then this sequence is said to be in Geometric Progression or Geometric Sum of G.P.
[tex]\rm a_n = ar^h[/tex]
Where a is the first term which is 4.
And r is the common ratio r = 2.
Therefore,
The number of cells present at the end of h hours if there are initially 4 of these cells is,
[tex]\rm n = ar^h\\ \\ \rm n = 4(2)^h[/tex]
Hence, the function represents the number of cells present at the end of h hours if there are initially 4 of these cells is [tex]\rm n = 4(2)^h[/tex].
To know more about Geometric Progression click the link given below.
https://brainly.com/question/14320920
