Respuesta :
2(3x-1) ≥ 4x-6
Distribute the 2 on the left side: 6x-2 ≥ 4x-6
Move terms to solve for x:
2x ≥ -4
x ≥ -2
Therefore, any value from -2 to ∞ are valid solutions.
Distribute the 2 on the left side: 6x-2 ≥ 4x-6
Move terms to solve for x:
2x ≥ -4
x ≥ -2
Therefore, any value from -2 to ∞ are valid solutions.
Answer:
x ≥ – 2. { -2, -1, 0, 1,2,.....
Step-by-step explanation:
Given : 2(3x – 1) ≥ 4x – 6.
To find : What value of x is in the solution set .
Solution : We have given that
2(3x – 1) ≥ 4x – 6.
Distribute 2 over (3x -1)
6x -2 ≥ 4x – 6.
On subtracting both sides by 4x
6x -2 - 4x ≥ – 6.
On adding both sides by 2
2x ≥ – 6+ 2.
2x ≥ – 4.
On dividing both sides by 2
x ≥ – 2.
Therefore, x ≥ – 2. { -2, -1, 0, 1,2,.....