Hello!
For the first one you use the equation for a right circular cone
The equation is[tex]A= \pi r(r+ \sqrt{h^{2} + r^{2} } [/tex]
A is area
r is radius which is half the diameter
h is height
Put in the values you know
[tex]A= \pi 7(7 + \sqrt{ 43^{2} + 7^{2} } [/tex]
Put this into a calculator and you get
1112.01
the answer is B
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Question 2
Knowing that the lateral area is 555pi and the radius is 15.1 the height is 33.51
We can use the Pythagorean theorem to find the slant height
[tex]a^{2} + b^{2} = c^{2} [/tex]
c is the slant height
a is height
b is radius
Put in the values you know
[tex]33.51^{2} + 15.1^{2} = c^{2} [/tex]
Square the numbers
1122.9 + 228.01 = c^2
Add
1350.91 = c^2
Take the square root of the number
c = 36.8
The answer is A
Hope this helps!
