(05.06)A chocolate bar measures 30 mm wide, 70 mm long, and four and one over two mm high. Will’s Wrapping Company is making a wrapper to cover the chocolate bar. Use the correct net and determine how much paper will be needed to make the wrapper.

Respuesta :

we know that

[surface area]=2*[area of the base]+[perimeter of the base]*height 
area of the base=30*70-----> 2100 mm²

perimeter of the base=2*(30+70)-----> 200 mm
height=4 1/2 mm-----> (4*2+1)/2-----> 9/2 mm
[surface area]=2*[2100]+[200]*9/2-----> 5100 mm²

the answer is
5100 mm²

Answer:

[tex]5100mm^{2}[/tex]

Step-by-step explanation:

Given : A chocolate bar measures 30 mm wide, 70 mm long, and four and one over two mm high

To Find :  how much paper will be needed to make the wrapper.

Solution :

Length of chocolate bar = 70 mm

Width of chocolate bar = 30 mm

Height of chocolate bar = [tex]4\frac{1}{2} =\frac{9}{2} =4.5 mm[/tex]

Since chocolate bar in in the shape of cuboid

Total surface area of cuboid : 2(length*width+width*height+height*length)

Thus the wrapper required to wrap chocolate = 2(70*30+30*4.5+4.5*70)

                                                                          = 2100+135+315

                                                                          = 2(2550)

                                                                          = 5100 square mm

Hence[tex]5100mm^{2}[/tex]  paper will be needed to make the wrapper.