Answer:
Step-by-step explanation:
The total surface area of rectangular pyramid is calculate as;
A = 2x(area of triangle with height 8ft and base 12ft) +2x(area of triangle with height 6ft and base 9.5ft)+ area of rectangle
[tex]A = 2\times(\frac{1}{2}\times(12)\times(8))+2\times(\frac{1}{2}\times(9.5)\times(6)) + (12\times6)[/tex]
[tex]A = 2\times(\frac{1}{2}\times96)+2\times(\frac{1}{2}\times57) + (72)[/tex]
[tex]A = 2\times(48)+2\times(\frac{1}{2}\times57) + (72)[/tex]
[tex]A = 96+2\times(\frac{1}{2}\times57) + (72)[/tex]
[tex]A = 96+57+72[/tex]
[tex]A = 225[/tex]
Hence, the total surface area of the rectangular pyramid is 225 cm²
The area of square pyramid is calculated as: [tex]\text{A} = 2(b\times l)+b^{2}[/tex]
in second figure we can see base 'b' is 6 and lateral height 'l' is 8.
so,
[tex]\text{A} = 2(b\times l)+b^{2}[/tex]
Put b = 6 and l = 8 in above formula,
[tex]= 2(6\times8) + 6^{2}[/tex]
[tex]= 2\times48 + 36[/tex]
[tex]= 96 + 36[/tex]
[tex]= 132[/tex]
Hence, the surface area of the square pyramid is 132 cm²
