The strength of the gravitational field is given by:
[tex]g= \frac{GM}{r^2} [/tex]
where
G is the gravitational constant
M is the Earth's mass
r is the distance measured from the centre of the planet.
In our problem, we are located at 300 km above the surface. Since the Earth radius is R=6370 km, the distance from the Earth's center is:
[tex]r=R+h=6370 km+300 km=6670 km= 6.67 \cdot 10^{6} m[/tex]
And now we can use the previous equation to calculate the field strength at that altitude:
[tex]g= \frac{GM}{r^2}= \frac{(6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2})(5.97 \cdot 10^{24} kg)}{(6.67 \cdot 10^6 m)^2} = 8.95 m/s^2[/tex]
And we can see this value is a bit less than the gravitational strength at the surface, which is [tex]g_s = 9.81 m/s^2[/tex].
