Answer: Option 'C' is correct.
Step-by-step explanation:
Since we have given that
the sides of the cubes are numbered 1 through 6,
So,
[tex]P(\text{ getting a 3})=\frac{1}{6}[/tex]
if they are both tossed ,
Probability (getting that they will both be a 3) is given by
[tex]=\frac{1}{6}\times \frac{1}{6}\\\\=\frac{1}{36}[/tex]
(∵[tex]\\P(\text{A and B})=P(A\cap B)=P(A).P(B)\\[/tex])
Therefore, Option 'C' is correct.
