when we have equals volumes of AgNO3 & NaNO2 so we can assume that the total volume = 1 L
so we need to new concentrations of:
[Ag+] = 0.04/2 = 0.02 M
and [NO2-] = 0.03 /2 = 0.015 M
So we need to get Q expression to compare it with the KsP value
when Q = [Ag+][NO2-]
by substitution:
Q = 0.02 * 0.015 = 0.0003
∴Q = 3 x 10^-4 by comparing this value with Ksp = 6 x 10^-4 (missing in your queston)
∴Q<Ksp
and when Q < Ksp this means that, this is an unsaturated solution and there is no precipitate will be observed.
