Respuesta :
The choices present in this question are:
a) N-H b) O-C c) O-N d) C-H e) O-H
The values of electronegativity given:
H = 2.1 C = 2.5 N = 3.0 O = 3.5
To determine the most polar bond we calculate the electronegativity difference in each bond and determine the highest value:
a) N-H = 3.0 - 2.1 = 0.9
b) O-C = 3.5 - 2.5 = 1
c) O-N = 3.5 - 3 = 0.5
d) C-H = 2.5 - 2.1 = 0.4
e) O-H = 3.5 - 2.1 = 1.4
So the correct answer is e) O-H
a) N-H b) O-C c) O-N d) C-H e) O-H
The values of electronegativity given:
H = 2.1 C = 2.5 N = 3.0 O = 3.5
To determine the most polar bond we calculate the electronegativity difference in each bond and determine the highest value:
a) N-H = 3.0 - 2.1 = 0.9
b) O-C = 3.5 - 2.5 = 1
c) O-N = 3.5 - 3 = 0.5
d) C-H = 2.5 - 2.1 = 0.4
e) O-H = 3.5 - 2.1 = 1.4
So the correct answer is e) O-H
The higher difference in the electronegativity has been in the O-H bond, the most polar bond is O-H.
The polarity of the bond can be defined as the difference in electronegativity.
- For N-H bond:
Electronegativity of N - Electronegativity of H
= 3 - 2.1
= 0.9
- For O-C bond:
Electronegativity of O - Electronegativity of C
= 3.5 - 2.5
= 1
- For O-N bond:
Electronegativity of O - Electronegativity of N
= 3.5 - 3
= 0.5
- For C-H bond:
Electronegativity of C - Electronegativity of H
= 2.5 - 2.1
= 0.4
- For O-H bond:
Electronegativity of O - Electronegativity of H
= 3.5 - 2.1
= 1.4
Since the higher difference in the electronegativity has been in the O-H bond, the most polar bond is O-H.
For more information about the polar bonds, refer to the link:
https://brainly.com/question/24775418