Respuesta :

x(x+1) = 132
x^2+x = 132
x^2+x-132 = 0

Factoring this gets you

(x+12)(x-11) = 0

x = 11 only because x = -12 is negative and you’re looking for positive integers

x+1
11+1
12

The two integers are 11 and 12

The integers are 11 and 12

An integer is a whole number. It does not have fractions or decimals. Example 4 , 10

Two consecutive integers are integers that follow each other on the number line. Example 2 and 3 ; 5 and 6

Let:

n represent the first integer

n + 1 represent the next integer

n x (n + 1) = 132

n² + n = 132

This can be solved using quadratic formula

n² + n - 132 = 0

multiply -132 and n² : -132n²

Determine factors o -132n² that add up to n

The factors are 12n and -11n

n² -11n + 12n - 132 = 0

n(n -11) +12(n -11) = 0

n + 12 = 0

n = -12

or

n - 11 = 0

n = 11

The number can either by -12 or 11

To determine the correct number, find the product of each number and the consecutive number

-12 x -13 = 156

11 x 12 = 132

11 and 12 are the correct integers

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