Respuesta :
x(x+1) = 132
x^2+x = 132
x^2+x-132 = 0
Factoring this gets you
(x+12)(x-11) = 0
x = 11 only because x = -12 is negative and you’re looking for positive integers
x+1
11+1
12
The two integers are 11 and 12
x^2+x = 132
x^2+x-132 = 0
Factoring this gets you
(x+12)(x-11) = 0
x = 11 only because x = -12 is negative and you’re looking for positive integers
x+1
11+1
12
The two integers are 11 and 12
The integers are 11 and 12
An integer is a whole number. It does not have fractions or decimals. Example 4 , 10
Two consecutive integers are integers that follow each other on the number line. Example 2 and 3 ; 5 and 6
Let:
n represent the first integer
n + 1 represent the next integer
n x (n + 1) = 132
n² + n = 132
This can be solved using quadratic formula
n² + n - 132 = 0
multiply -132 and n² : -132n²
Determine factors o -132n² that add up to n
The factors are 12n and -11n
n² -11n + 12n - 132 = 0
n(n -11) +12(n -11) = 0
n + 12 = 0
n = -12
or
n - 11 = 0
n = 11
The number can either by -12 or 11
To determine the correct number, find the product of each number and the consecutive number
-12 x -13 = 156
11 x 12 = 132
11 and 12 are the correct integers
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