The normal boiling point of c2cl3f3 is 47.6°c and its molar enthalpy of vaporization is 27.49 kj/mol. what is the change in entropy in the system in j/k when 24.1 grams of c2cl3f3 vaporizes to a gas at the normal boiling point?

Respuesta :

The change in entropy in the system in J/k when 24.1 grams of C₂Cl₃F₃ vaporizes to a gas at the normal boiling point is 11J/K.

How we calculate the change in entropy?

Change in entropy of the system will be calculated from the below formula:

ΔG = ΔH - TΔS, where

ΔG = Gibb's free energy = 0

ΔH = molar enthalpy of C₂Cl₃F₃ = 27.49 kJ/mol = 27490 J/mol

T = temperature = 47.6° C = 320.6 K

ΔS = change in entropy = to find?

For the calculation first we have to find the moles of 24.1g of C₂Cl₃F₃ because in system only 1 mole of the substance is not present. So,

Moles (n) = 24.1g / 187.3764g/mol = 0.129 moles

Now we calculate the change in entropy of the system by putting all the above values in the below equation as:

ΔS = n.ΔH / T

ΔS = 0.129mol × 27490J/mol / 320.6 K = 11J/K.

Hence, the change in entropy of the system is 11J/K.

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