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ChemistryHelper2024
HNO₂ and NaNO₂ is considered as acidic buffer because HNO₂ is considered as weak acid and NaNO₂ is the conjugate base of this acid.

To find the original pH, we just use the Henderson-Hasselbach equation:
pH = pKa + log [tex] \frac{[Salt]}{[Acid]} [/tex]

so pH = 3.4 + log [tex] \frac{(1.0 M)}{(0.1 M)} [/tex] = 4.4
mixter17
Hello!

For solving this question, you need to know the value of the pKa of HNO₂ before applying the Henderson-Hasselbach's equation. The pKa of HNO₂ can be found in tables or online and is 3,15. Now you can apply the equation in the following way:

[tex]pH=pKa+log( \frac{[NO_2^{-}] }{[HNO_2]} )=3,15+log( \frac{1,00M}{0,100M})=4,15[/tex]

So, the pH of this solution of HNO₂ and NaNO₂ should be 4,15

Have a nice day!

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