area of the circle = πr²
2 quarter circles give one half circle, area of the half circle =πr²/2=(π*5²)/2
Area of the right triangle = 1/2*b*h, but here base and height are equal , so we can write for area of the triangle 5*5/2 =25/2
All area= (π*5²)/2 + 25/2≈51.8 cm²
Answer is C
