Answer:
Using the formula:
[tex]\text{Weight} = \text{Density} \times \text{Volume}[/tex]
As per the statement:
Given a 10 foot length of tree trunk with a radius of 3 feet.
Volume of tree trunk(V) is given by:
[tex]V = \pi r^2h[/tex]
where, r is the radius and h is the length of the tree trunk.
Substitute r = 3 ft and h = 10 ft and use [tex]\pi = 3.14[/tex]
then;
[tex]V = 3.14 \cdot 3^2 \cdot 10 = 282.6 ft^3[/tex]
It is also given it has a density of 45 lb/ft^3
then;
[tex]\text{Weight} = 45 \cdot 282.6 = 12717 Ib[/tex]
Therefore, the the weight of the tree trunk section is, 12,717 Ib
