1st Shape: A combination of a trapezium and a rectangle We know the area formulas of rectangles → Area = length × width | And Trapeziums → Area = [tex] \frac{1}{2} (base1+base2)(height)[/tex]
We are given: Length of rectangle and base 2 of trapezium = 20 in Width of rectangle = 16 in Base 1 of trapezium = 9 in Height of trapezium = 21 - 16 = 5 in
Apply the formulas Area of rectangle = 20 × 16 = 320 in² Area of trapezium = [tex] \frac{1}{2} [/tex] ( 9 + 20 )(5) = 72.5 in²
Add both areas if necessary = 320 + 72.5 = 392.5 in²
2nd Shape: It is a trapezium
We know the area formula of a trapezium Area = [tex] \frac{1}{2}(base 1 + base 2 )(height) [/tex]
We know the Base 1 = 8 units Base 2 = 16 units Height = 14 units
Apply the formula Area = [tex] \frac{1}{2} (8+16)(14)[/tex] = 168 units²
3rd Shape: It is a trapezium
We know the: Base 1 = 7 units Base 2 = 24 units Height = 24 units
Apply the formula Area = [tex] \frac{1}{2}(7+24)(24) [/tex] = 372 units²
4th Shape: It is a trapezium
We know the: Base 1 = 4 units Base 2 = 8 units Height = 6 units
Apply the formula: Area = [tex] \frac{1}{2} ( 4 + 8 )(6)[/tex] = 36 units²
