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Set up, but do not evaluate, an integral for the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis.

y = sqrt(x), y = x^2; about y = 2
or [tex]y = \sqrt{x}, y = x^2[/tex]; about [tex]y = 2[/tex]

Respuesta :

JцstinBieber
A washer has outer radius [tex]2-x^2[/tex] and inner radius [tex]2 - \sqrt{x}[/tex]

[tex]\displaystyle V = \int_0^1 \pi\Big[ \left( 2 - x^2 \right)^2 - \left( 2 - \sqrt{x}\right)^2\Big] dx[/tex]
Ver imagen JцstinBieber

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