Respuesta :
In order to prepare a 250 ml solution of CuSO₄ of 0.5 M we need to calculate the amount of CuSO₄ requires. So, as we know,
Molarity = Moles / Volume of Solution
Also,
Molarity = (Mass ÷ M.mass) / Volume of Solution
Solving for Mass,
Mass = Molarity × M.mass × Volume
Putting Values, ∴ 250 ml = 0.25 dm³
Mass = 0.5 mol.dm⁻³ × 159.6 g.mol⁻¹ × 0.25 dm³
Mass = 19.95 g
Step 2:
Take 19.95 g of CuSO₄, add it to volumetric flask and add distilled water upto the mark of 250 ml. The resulting solution will be of concentration 0.5 M.
Molarity = Moles / Volume of Solution
Also,
Molarity = (Mass ÷ M.mass) / Volume of Solution
Solving for Mass,
Mass = Molarity × M.mass × Volume
Putting Values, ∴ 250 ml = 0.25 dm³
Mass = 0.5 mol.dm⁻³ × 159.6 g.mol⁻¹ × 0.25 dm³
Mass = 19.95 g
Step 2:
Take 19.95 g of CuSO₄, add it to volumetric flask and add distilled water upto the mark of 250 ml. The resulting solution will be of concentration 0.5 M.
Answer:
B) 0.125 mol CuSO4.
Explanation:
M =
moles solute
liters solution
and solve for moles solute. moles = M x L Be sure to convert milliliters to liters.