Using the distance between two points, it is found that the perimeter of triangle ABC is of 16 units.
What is the distance between two points?
Suppose that we have two points, [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]. The distance between them is given by:
[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
The perimeter is the sum of the lengths of all sides of the triangle, and the lengths are given by the distance, hence:
- [tex]l_1 = D_{BA} = \sqrt{(2 - (-1))^2+(5 - 1)^2} = 5[/tex]
- [tex]l_2 = D_{CA} = \sqrt{(5 - (-1))^2+(1 - 1)^2} = 6[/tex]
- [tex]l_3 = D_{BC} = \sqrt{(2 - 5)^2+(5 - 1)^2} = 5[/tex]
Then, the perimeter is:
5 + 6 + 5 = 16 units.
More can be learned about the distance between two points at https://brainly.com/question/18345417
#SPJ2
