Answer: The molarity of the solution is 0.19 M
Explanation:
To calculate the molarity of the solution, we use the equation given as:
[tex]\text{Molarity}=\frac{\text{Mass of solute(in grams)}}{\text{Molar mass of solute(in g/mol)}\times \text{Volume of solution (in L)}}[/tex]
We are given:
Mass of NaOH = 11.5 g
Molar mass of NaOH = [tex][23+16+1]g/mol=40g/mol[/tex]
Volume of the solution = 1.5 Liters
Putting values in above equation, we get:
[tex]\text{Molarity of solution}=\frac{11.5g}{40g/mol\times 1.5L}=0.19mol/L=0.19M[/tex]
Hence, the molarity of the solution is 0.19 M
