Respuesta :
The ratio of effusion of rates of oxygen (O2) to Hydrogen (H2) is calculated as follows
rate of O2/ rate of H2 = square root of molar mass of H2/molar mass of O2
= square root = 2 /32 = 0.25
rate of O2/ rate of H2 = square root of molar mass of H2/molar mass of O2
= square root = 2 /32 = 0.25
Answer:
0.251
Explanation:
According to the Graham's law, the rate of effusion of a gas (r) is inversely proportional to the square root of its molar mass (M). The ratio of effusion rates of oxygen (O₂) to hydrogen (H₂) is:
[tex]\frac{rO_{2}}{rH_{2}} =\sqrt{\frac{M(H_{2})}{M(O_{2})}} =\sqrt{\frac{2.02g/mol}{32.00g/mol}} =0.251[/tex]