There are 36 chocolates in a box, all identically shaped. there 10 are filled with nuts, 12 with caramel, and 14 are solid chocolate. you randomly select one piece, eat it, and then select a second piece. find the probability of selecting a solid chocolate candy followed by a nut candy.

Total chocolates = 36
Total with nuts = 10
Total with caramel = 12
Total with Solid chocolate = 14

P(Solid Chocolate) = 14/46 = 7/18

Answer: 7/18

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JeanaShupp JeanaShupp · Answer 2 · 2019-08-13T08:39:31+02:00

Answer: [tex]\dfrac{1}{9}[/tex]

Step-by-step explanation:

Given : The total number of chocolates in the box = 36

The number of chocolates filled with solid chocolate =14

The number of chocolates filled with nuts = 10

Now, the probability of selecting a solid chocolate candy is given by :-

[tex]=\dfrac{14}{36}[/tex]

Now the chocolates left in box = 36-1=35

The probability of selecting next chocolate a nut candy will be :-

[tex]=\dfrac{10}{35}[/tex]

Now, the probability of selecting a solid chocolate candy followed by a nut candy will be:_

[tex]=\dfrac{14}{36}\times\dfrac{10}{35}=\dfrac{1}{9}[/tex]