Respuesta :
CH3COONa+HBr ----> NaBr + CH3COOH
CH3COO⁻ +H⁺ ------> CH3COOH , because CH3COOH is a weak acid
CH3COO⁻ +H⁺ ------> CH3COOH , because CH3COOH is a weak acid
Answer: The net ionic equation is given below.
Explanation:
Net ionic equation of any reaction does not include any spectator ions.
Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.
The chemical equation for the reaction of hydrobromic acid and sodium acetate is given as:
[tex]CH_3COONa(aq.)+HBr(aq.)\rightarrow CH_3COOH(aq.)+NaBr(aq.)[/tex]
Ionic form of the above equation follows:
[tex]CH_3COO^-(aq.)+Na^+(aq.)+H^+(aq.)+Br^-(aq.)\rightarrow CH_3COO^-(aq.)+H^+(aq.)+Na^+(aq.)+Br^-(aq.)[/tex]
As, sodium and bromine ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.
Acetic acid is a weak acid, so it will not completely dissociate into its ions.
The net ionic equation for the above reaction follows:
[tex]H^+(aq.)+CH_3COO^-(aq.)\rightarrow CH_3COOH(aq.)[/tex]
Hence, the net ionic equation is given above.
