The order doesn't matter.
[tex]k [/tex] objects can be chosen out of [tex] n [/tex] objects, when the order doesn't matter, in [tex] C(n,k)=\dfrac{n!}{k!(n-k)!} [/tex] ways.
So, the answer is [tex] C(7,2)\cdot C(5,3)=\dfrac{7!}{2!5!}\cdot\dfrac{5!}{3!2!}=\dfrac{6\cdot7}{2}\cdot\dfrac{4\cdot5}{2}=210 [/tex] ways.
