Respuesta :
[Ar]4s²3d¹⁰4p⁴
We see that the last level is this element is 4, so this element should be in
4th period, it has 4 p-electrons, so it should be in 16th group.
4th period, 16th group - it is Se.
You can also go to the next element after Ar, and count beginning of this element 16. (2+10+4 =16 electrons)
From "K" (where K is the first) you count to 16 and it is going to be Se.
We see that the last level is this element is 4, so this element should be in
4th period, it has 4 p-electrons, so it should be in 16th group.
4th period, 16th group - it is Se.
You can also go to the next element after Ar, and count beginning of this element 16. (2+10+4 =16 electrons)
From "K" (where K is the first) you count to 16 and it is going to be Se.
The element with the 34 atomic number belonging to group 16 is Selenium (Se).
To identify the element from the given electronic configuration, the atomic number has to be elucidated.
The atomic number of Argon is 18.
The electronic configuration has been:
[tex]\rm [Ar]\;4s^2\;3d^1^0\;4p^4[/tex]
The number of electrons in addition to arogon electrons are:
= 18 + 2 + 10 + 4
= 34
The electronic configuration elucidates that the element has the last electron in the 4p orbital, thus belonging to group 16.
The element with the 34 atomic number belonging to group 16 is Selenium (Se).
For more information about the elements in the periodic table, refer to the link:
https://brainly.com/question/16762037
