The solution for the rotational flywheel is:
L = I x ω
But we need to solve for l first, the computation is:
I = 1/2 m r^2 = 1/2 (10) (0.090^2) = 0.0405 kg*m^2
ω = 320 rad/s
So plugging in the information above, will give us:
L = 0.0405 * 320 = 12.96 kg*m^2/s or about 13 kg*m^2/s
