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19-03-2018
Mathematics

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The lengths of trout in a lake are normally distributed with a mean of 30 inches and a standard deviation of 4.5 inches. Enter the z-score of a trout with a length of 28.2 inches.

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MsEHolt MsEHolt

29-03-2018

The z-score would be -0.4.

The formula for z-scores is

[tex]z=\frac{X-\mu}{\sigma}[/tex]

Using our information, we have:
[tex]z=\frac{28.2-30}{4.5}= \frac{-1.8}{4.5}=-0.4[/tex]

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