The first term of an arithmetic sequence is -3 and the fifteenth term is 53. What is the common difference of the sequence? 14/13 25/7 4

Respuesta :

[tex]a_1=-3 \\ a_{15}=53 \\ \\ d= \frac{53-(-3)}{15-1}= \frac{56}{14}=4[/tex]

The answer is d=4

Answer:

The common difference of the arithmetic sequence is:

                                       4

Step-by-step explanation:

We kn ow that if the first term of an arithmetic sequence is a and d is the common difference of the sequence then the nth term of the sequence is given by the formula:

[tex]a_n=a+(n-1)d[/tex]

Here we are given:

[tex]a=-3[/tex]

and

[tex]a_15=53\\\\i.e.\\\\a+(15-1)d=53\\\\i.e.\\\\a+14d=53[/tex]

Now using the value of a we have:

[tex]-3+14d=53\\\\i.e.\\\\14d=56\\\\i.e.\\\\d=4[/tex]