Describe the vector as an ordered pair. Round the coordinates to the nearest tenth. The diagram is not drawn to scale.

ANSWER
[tex]
\angle19.4,50.4 \: > [/tex]
EXPLANATION
The given vector has magnitude 54 units.
The vector is making an angle of 69° with the x-axis.
The horizontal component of the vector is
[tex] = 54 \cos(69) [/tex]
[tex] = 19.35[/tex]
To the nearest tenth, we have,
[tex] = 19.4[/tex]
The vertical component is
[tex] = 54 \sin(69 \degree) [/tex]
[tex] = 50.41[/tex]
[tex] = 50.4[/tex]
to the nearest tenth.
The required vector is
[tex]
\angle19.4,50.4 \: > [/tex]
The components of the vector with magnitude 54 and the angle of 69° from the horizontal can be written as <19.3519, 50.4133>.
A vector is a quantity that has both magnitude and direction. It has two components a vertical component(Sine) and a horizontal component(Cosine). The component of a vector can be written as,
Vertical component, [tex]V_y = \vec V\ Sin(\theta)[/tex]
Horizontal component, [tex]V_x = \vec V\ Cos(\theta)[/tex]
We know that a vector can be divided into two components a horizontal component and a vertical component, therefore, the vector components can be written as,
[tex]V_y = \vec V Sin\theta\\\\V_y = 54\ Sin(69^o)\\\\V_y = 50.4133[/tex]
[tex]V_x = \vec V Cos\theta\\\\V_x = 54\ Cos(69^o)\\\\V_x = 19.3519[/tex]
Hence, the components of the vector with magnitude 54 and the angle of 69° from the horizontal can be written as <19.3519, 50.4133>.
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