Respuesta :
The solution to your question is a=-2. Hope this helped you. I just took the test. So I know it is right. Can you please give me Brainliest?
Answer:
a=-2 is extraneous solution.
Step-by-step explanation:
Given the equation
[tex]\frac{3}{a+2}+\frac{2}{a}=\frac{4a-4}{a^2-4}[/tex]
we have to find the extraneous solution.
An extraneous solution is a solution to an equation, that emerges from the process of solving the problem but is not a valid solution to the problem.
[tex]\frac{3}{a+2}+\frac{2}{a}=\frac{4a-4}{a^2-4}[/tex]
[tex]\frac{3}{a+2}+\frac{2}{a}=\frac{4a-4}{a^2-4}\\\\\frac{3a+2(a+2)}{a(a+2)}=\frac{4(a-1)}{a^2-4}\\\\\frac{5a+5}{a(a+2)}=\frac{4(a-1)}{a^2-4}[/tex]
On solving, we get
The solution is a=4 and a=-2
Here the solution a=-2 is the valid solution as it makes the denominator 0.
⇒ a=-2 is extraneous solution.
Option 1 is correct.
