Answer:
D). Y'= [tex]4x^{5}-12x^{4}+6x[/tex] and y'= [tex]5x^{3}-2x[/tex]
Step-by-step explanation:
We are given the equation [tex]4x^{5}-12x^{4}+6x=5x^{3}-2x[/tex].
On simplifying this equation, we get [tex]4x^{5}-12x^{4}-5x^{3}+8x=0[/tex]
i.e. Let, Y'= [tex]4x^{5}-12x^{4}+6x[/tex] and y'= [tex]5x^{3}-2x[/tex]
Now, according to the options,
A) Y = [tex]-4x^{5}+12x^{4}-6x[/tex] = -Y' , that means the graph will be inverse of the required graph.
B) As the coefficient of 'x' in our given equation and the equation of option B are different, both will have different graphs.
C) As y = [tex]-5x^{3}+2x[/tex] = -y', this means that the graph will be inverse of the required graph.
Hence, all above options are discarded and so option D is correct.
