Answer:
x=-5, x=1
Step-by-step explanation:
y=x-8/x^2+4x-5
[tex]y=\frac{x-8}{x^2+4x-5}[/tex]
When denominator becomes 0 in a rational function then there will be a break in the graph
To find any points of discontinuity for the rational function
, we set the denominator =0 and solve for x
x^2 + 4x -5 =0
Now we factor x^2 +4x -5
product is -5 and sum = 4
5 * (-1) = -5
5 +(-1) = 4
(x+5)(x-1) =0
set each factor =0 and solve for x
x+5=0 , so x= -5
x-1=0 , so x= 1
x=-5, x=1 are the points of discontinuity for the rational function
