Jen Butler has been pricing speed pass train fares for a group trip to new york. three adult and four children must pay $122. two adults and three children must pay $87. find the price of the adult ticket and the price of the child

Respuesta :

Let price of adult ticket is $x

And price of child ticket is $y

So we can make two equations using the given data

[tex] 3x+4y = 122 [/tex]

[tex] 2x+3y = 87 [/tex]

Now we can use eliminator method to solve the two equations

Multiply first equation by 2 and second equation by -3

[tex] 2(3x+4y = 122) [/tex]

[tex] -3(2x+3y = 87) [/tex]

[tex] 6x+8y = 244 [/tex]

[tex] -6x-9y =-261 [/tex]

now add both the equations so we get

[tex] 6x-6x+8y-9y=244-261 [/tex]

combine the like terms

[tex] -y=-17 [/tex]

Divide both sides by -1

[tex] y=17 [/tex]

Plug y=17 in any one of the equations to solve for x

[tex] 3x+4(17) = 122 [/tex]

[tex] 3x+68 = 122 [/tex]

Subtract 68 from both sides

[tex] 3x = 54 [/tex]

Divide both sides by 3

[tex] x=18 [/tex]

So x=18 and y=17


So

Price of adult ticket= $18

Price of child ticket = $17