Respuesta :
According to this formula:
pH = - log [H]
And, pOH = - log [OH] >>> (1)
Where, pH + pOH = 14 >>> (2)
∵ the hydroxide ion concentration = (OH-) = 10 ^ -10 M
from (1) and (2) and by substitution:
∴ pOH = - log [10^-10] = 10
∴ pH = 14 - 10 = 4
pH = - log [H]
And, pOH = - log [OH] >>> (1)
Where, pH + pOH = 14 >>> (2)
∵ the hydroxide ion concentration = (OH-) = 10 ^ -10 M
from (1) and (2) and by substitution:
∴ pOH = - log [10^-10] = 10
∴ pH = 14 - 10 = 4
pH is the potential of hydrogen.
pH = -log₁₀(H+)
while, pOH = -log₁₀(OH-)
But; pH + pOH =14
Therefore; for a solution with a concentration of (OH-) of 10^-10
The pOH= -log(10^-10)
= 10
Therefore pH =14-10
= 4
pH = -log₁₀(H+)
while, pOH = -log₁₀(OH-)
But; pH + pOH =14
Therefore; for a solution with a concentration of (OH-) of 10^-10
The pOH= -log(10^-10)
= 10
Therefore pH =14-10
= 4