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budwilkins
Start by seeing where the lines go. They cross (intersect) at (1, -1). We can use this to check later.
Now for slope: green is -4/2 = -2
pink is 4/2 = 2
Now we can create the equations
Let's make green = g(x) and pink = p(x)
if we use y = mx + b, then the green has a y-intercept (b) of +1
So g(x) = -2x + 1
pink has a y-intercept of -3, so p(x) = 2x - 3
Now let's plug n play: put our solutions x into each equation and confirm that it makes the y = -1
g(x) = -2x + 1 = -2(1) + 1 = -2+1 = -1
p(x) = 2x - 3 = 2(1) - 3 = 2-3 = -1

✔ YES THEY ARE CONFIRMED
abidemiokin

The required systems of equations are y = 1 and y = 5/3 x - 3

For us to get the required equation, we need to find the equation of both lines.

The standard form of the equation of a straight line is expressed as:

[tex]y=mx+b[/tex]

m is the slope of a line

b is the y-intercept

For the green line, the y- intercept is 1

Using the coordinate points (0, -1) and (1, -1) to get the slope

[tex]Slope =\frac{-1+1}{1-0}\\Slope = 0[/tex]

The equation of the green line will be y = 0x + 1 i.e y = 1

For the red line, the y-intercept is -3

Get the slope of the green line

Using the coordinate points (0, -2) and (3, 3) to get the slope

[tex]Slope =\frac{3+2}{3-0}\\Slope = 5/3[/tex]

The equation of the red line will be y = 5/3 x - 3

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