Respuesta :
when v= 4.8 m/s:
E.K=mv²/2
=3,1(4.8)²/2
=35.712J
when v= 2(4.8):
E.K=mv²/2
=3.1(9.6)²/2
=142.848J
E.K=mv²/2
=3,1(4.8)²/2
=35.712J
when v= 2(4.8):
E.K=mv²/2
=3.1(9.6)²/2
=142.848J
The Kinetic energy of the same cart at twice the speed is [tex]142.848 J[/tex].
What is kinetic energy?
The kinetic energy of an object is the energy which it possesses due to its motion. It gives the work needed to accelerate a body of a given mass from rest to its stated velocity. To calculate kinetic energy
[tex]K.E = \frac{1}{2}m v^{2}[/tex]
Kinetic energy depends on the velocity of the object which means that when the velocity of an object doubles, its kinetic energy quadruples.
Kinetic energy must always be either zero or a positive value.
Kinetic energy is not a vector.
Given:
Mass, [tex]m = 3.1 Kg[/tex]
Velocity, [tex]v = 4.8 m/s[/tex]
The kinetic energy is,
[tex]K.E = \frac{1}{2}m v^{2}\\K.E = \frac{1}{2}*3.1*4.8^{2}\\K.E = 35.712 J[/tex]
As speed of cart is twice the original speed,
Velocity, [tex]v = 9.6 m/s[/tex]
The kinetic energy is,
[tex]K.E = \frac{1}{2}m v^{2}\\K.E = \frac{1}{2}*3.1*9.6^{2}\\K.E = 142.848 J[/tex]
As speed of cart is twice the original speed, the kinetic energy is quadruples.
To learn more about Kinetic energy here
https://brainly.com/question/15764612
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